Tolong dibantu jawab + Caranya [tex]f(x) = \sqrt{2x - 3} [/tex] g(x) = x² + 1 (FoG)(2) =
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Pertanyaan
Tolong dibantu jawab + Caranya
[tex]f(x) = \sqrt{2x - 3} [/tex]
g(x) = x² + 1
(FoG)(2) =
[tex]f(x) = \sqrt{2x - 3} [/tex]
g(x) = x² + 1
(FoG)(2) =
1 Jawaban
-
1. Jawaban Anonyme
g(x) = x² + 1
g(2) = 2² + 1
g(2) = 5
f(x) = √(2x - 3)
(fog)(2)
= f(g(2))
= f(5)
= √(2 . 5 - 3)
= √(10 - 3)
= √7