Matematika

Pertanyaan

3 log 1/9 + √2 log 9 . 3 log 16/
2 log 10 . 2 log.5

1 Jawaban

  • (3log 1/9 + √2log 9 . 3log 16)/(2log 10-2log 5)
    = (3log 3^-2 + 2^1/2 log 3^2.3log 2^4)/(2log (10:5))
    = (-2.3log 3 + 2/(1/2).2log 3.4.3log 2)/(2log 2)
    = (-2 + 2.2/1.4.2log 3.3log 2)/1
    = (-2+8.2log 2)
    = -2+8
    = 6

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