9e + 5.000 cm3= dm3 2e+4de= cm3 4e+48cm3= cc 5me+1.400e= cc
Matematika
april424
Pertanyaan
9e + 5.000 cm3= dm3
2e+4de= cm3
4e+48cm3= cc
5me+1.400e= cc
2e+4de= cm3
4e+48cm3= cc
5me+1.400e= cc
1 Jawaban
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1. Jawaban Roamsaw
Itu bukan "e" lo dek tapi liter, simbolnya l kecil yang ditulis latin.
Nomor 1
[tex]9 \: liter \: + 5000 {cm}^{3} \\ = 9 {dm}^{3 } + 5 {dm}^{3} \\ = 14 {dm}^{3} [/tex]
Nomor 2
[tex]2 \: liter + 4 \: desiliter \\ 2000 {cm}^{3} + 400 {cm}^{3} = 2400 {cm}^{3} [/tex]
Nomor 3
[tex]4 \: liter+48 {cm}^{3} \\ = 4000 {cm}^{3} + \: 48 {cm}^{3} \\ = 4048 \: {cm}^{3} \\ = 4048 \: cc[/tex]
Nomor 4
[tex]5 \: mililiter + 1400 \: liter \\ = 5 \: mililiter + 1400.000 \: mililiter \\ = 1400.005 \: mililiter \\ = 1400.005 \: cc[/tex]