Persamaan lingkaran berpusat di A (5,5) melalui sumbu koordinat cartesius berbentuk.... A. (x-5)² + (y-5)² = 5 B. (x-5)² + (y-5)² = 10 C. (x-5)² + (y-5)² = 25 D
Matematika
ardianibelia
Pertanyaan
Persamaan lingkaran berpusat di A (5,5) melalui sumbu koordinat cartesius berbentuk....
A. (x-5)² + (y-5)² = 5
B. (x-5)² + (y-5)² = 10
C. (x-5)² + (y-5)² = 25
D. (x-5)² + (y-5)² = 30
E. (x-5)² + (y-5)² = 50
A. (x-5)² + (y-5)² = 5
B. (x-5)² + (y-5)² = 10
C. (x-5)² + (y-5)² = 25
D. (x-5)² + (y-5)² = 30
E. (x-5)² + (y-5)² = 50
1 Jawaban
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1. Jawaban Anonyme
jawab
P(a,b)= (5,5)
r = jarak (5,5) ke (o,o)
r = 5√2
r² = 50
(x - 5)^2 + (y-5)^2 = 50