persamaan garis lurus melalui titik A(-2,5) dan sejajar garis 3y - 4x -8 = 0 adalah ......

Kelas 8 Matematika
Bab Persamaan Garis

ax + by + c = 0, sejajar, (p, q)
ax + by - (ap + bq) = 0

-4x + 3y - 8 = 0, sejajar, (-2, 5)
-4x + 3y - (-4 . (-2) + 3 . 5) = 0
-4x + 3y - (8 + 15) = 0
-4x + 3y - 23 = 0
4x - 3y + 23 = 0