Tolong banget bantuin dong ...
Fisika
Paulinafk7
Pertanyaan
Tolong banget bantuin dong ...
1 Jawaban
-
1. Jawaban AnugerahRamot
Dinamika Rotasi
• Kesetimbangan benda
α = 37°⇒ sin α = ⅗⇒cos α = ⅘
β = 53°⇒sin β = ⅘⇒cos β = ⅗
m = 10 kg
g = 10 m/s² ... Anggap
w = mg = 10 × 10 = 100 N
Tinjau Sumbu x
∑ Fx = 0
T₁ cos α - T₂ cos β = 0
T₁ cos α = T₂ cos β
T₁ × ⅘ = T₂ × ⅗
4T₁ = 3T₂
T₁ = ¾ T₂ ...(i)
Tinjau Sumbu y
∑ Fy = 0
T₁ sin α + T₂ sin β - w = 0
(¾ T₂) × ⅗ + T₂ × ⅘ = 100
T₂ = 80 N
Dan
T₁ = ¾ T₂
T₁ = ¾ × 80
T₁ = 60 N