Gunakan rumus abc untuk menyelesaikan persamaan kuadrat 4x²+3x-10=0

4x² + 3x - 10 = 0
a = 4 ; b = 3 ; c = -10

(-b ± √b² - 4ac)/ 2a
= (-3 ± √9 - 4(4)(-10) ) / 2(4)
= (-3 ± √9 + 160) / 8
= (-3 ± √169) / 8
= (-3 ± 13 ) / 8
X1 = (-3 + 13) / 8 = 10/8 = 5/4
x2 = (-3 - 13) / 8 = -16/8 = -2