1. persamaan garis yg melalui titik (-3,1) dan bergradien 3 adalah.... 2. diketahui rumus fungsi f (x) = ax + b. jika f(2) = -2 dan f (-3) = 13 maka nilai f (4

1. Persamaan Garis Lurus
y = m(x-x1) + y1
y = 3(x+3) + 1
y = 3x + 9 + 1
y = 3x + 10

2. Fungsi
f(x) = ax + b
f(2) = 2a + b
-2 = 2a + b

f(-3) = -3a + b
13 = -3a + b

-2 = 2a + b
13 = -3a + b
------------------ -
-15 = 5a
a = -15/5
a = -3

-2 = 2a + b
-2 = 2 . -3 + b
-2 = -6 + b
-b = -6 + 2
-b = -4
b = 4

f(x) = ax + b
f(4) = 4 . (-3) + 4
f(4) = -12 + 4
f(4) = -8

Semoga membantu :)