suatu fungsi f(×) =ax+b. memiliki nilai f(1)=7 dan f(3)=5 tentukan nilai f(0). a. 9 b. 8 c. 0 d. -1 tolong dibantu besok mau ulangann

Kelas 8 Matematika
Bab Fungsi

f(x) = ax + b 

f(1) = a + b = 7
f(3) = 3a + b = 5

3a + b = 5
a + b = 7
---------------- -
2a = -2
a = -1

a + b = 7
-1 + b = 7
b = 7 + 1
b = 8

f(x) = -x + 8

f(0) = -0 + 8
f(0) = 8

1 = 7
3 = 5
Kurangin
-2y = 2x + (5 - 21)
-2y = 2x - 16 ( bagi (-2) )
Y= f (x) = - x + 8
Jadi, f (0) = 8 (b)