Integral yang atas 1 ,yang bawah -2 (2x+n) dx = 15. nilai n = makasihh ...

(2x + n) dx = 15
x² + nx = 15
masukan {1, -2}
1 + n - ((-2)² - 2n) = 15
n = 6

∫(2x + n) dx [1 _ -2] = 15
x² + nx [1 _ -2] = 15
(1² + 1n) - ((-2)² + (-2)n) = 15
(1 + n) - (4 - 2n) = 15
1 + n - 4 + 2n = 15
3n - 3 = 15
3n = 15 + 3
n = 18/3
n = 6