tolong bantu butuh sekarang please

[tex] \frac{ {2}^{n + 4} - 2 \times {2}^{n} }{2 \times {2}^{n + 3} } + {2}^{ - 3} = \frac{ {2}^{n} \times {2}^{4} - 2 \times {2}^{n} }{2 \times {2}^{n} \times {2}^{3} } + \frac{1}{ {2}^{3} } \\ = \frac { {2}^{n}({2}^{4} - 2)}{ {2}^{n}(2 \times{2}^{3}) } + \frac{1}{ {2}^{3} } \\ =\frac{ {2}^{4} - 2 }{2 \times {2}^{3} } + \frac{1}{ {2}^{3} } = \frac{16 - 2}{16} + \frac{1}{8} = \frac{14}{16} + \frac{2}{16} = 1[/tex]