1. persamaan garis yg melalui titik (-3,1) dan bergradien 3 adalah.... 2. diketahui rumus fungsi f (x) = ax + b. jika f (2) = -2 dan f (-3) = 13 maka nilai f (4

1. y-y1 = m(x-x1)
y-1 = 3(x+3)
y-1 = 3x+9
y= 3x+10

2. f(2) = 2a+b = -2
f(-3) =-3a+b = 13
dieleminasi. jadinya, 5a = -15 , a=3
substitusi : 2a+b = -2
6+b = -2 ---> b= -8
f(4) = 4.3 -8 = 12-8 = 4