Tolong jawab dari nomir 10 sampai 13

[tex] \frac{ \sqrt{32} }{ \sqrt{108} } = \frac{ \sqrt{16 \times 2} }{ \sqrt{36 \times 3} } = \frac{4 \sqrt{2} }{6 \sqrt{3} } = \frac{2 \sqrt{2} }{3 \sqrt{3} } [/tex]
[tex]6 \sqrt{147} - 4 \sqrt{98} = 6 \sqrt{49 \times 3} - 4 \sqrt{49 \times 2} = 6 \times 7 \sqrt{3} - 4 \times 7 \sqrt{2} = 42 \sqrt{3} - 28 \sqrt{3} [/tex]
[tex]9 \sqrt{350} + 9 \sqrt{60} = 9 \sqrt{25 \times 14} + 9 \sqrt{15 \times 4} = 9 \times 5 \sqrt{14} + 9 \times 2 \sqrt{15} = 45 \sqrt{14} + 18 \sqrt{15} [/tex]