Tolong dong, nomor 4 saja
Matematika
ranizainita
Pertanyaan
Tolong dong, nomor 4 saja
1 Jawaban
-
1. Jawaban aliffirdazz
panjang TU
[tex] \sqrt{ {20}^{2} + {48}^{2} } \\ = \sqrt{400 + 2304} \\ = \sqrt{2704} \\ = 52 \: cm[/tex]
panjang TR
[tex] \sqrt{ {20}^{2} + {52}^{2} } \\ = \sqrt{400 + 2704} \\ = \sqrt{3104} \\ [/tex]