Integral dari (x-1)^2 / √x dx =... ^= pangkat

jawab

∫ (x  - 1)² (x)^(-1/2) dx

∫ (x² - 2x + 1)(x^(-1/2) dx

∫ x^(3/2) - 2 x^(1/2) + x^(-1/2) dx

= 2/5 x^2 √x - 4/3  x√x  + 1/2 √x