Mohon dibantu Kelas 10 Matematika beserta caranya

[tex](fog)(x) = 4( {x}^{2} - 3x + 3) \\ f(g(x)) = 4( {x}^{2} - 3x + 3) \\ g(x) + 3 = 4( {x}^{2} - 3x + 3) \\ g(x) = 4 {x}^{2} - 12x + 9 \\ y = {(2x - 3)}^{2} \\ x = {(2y - 3)}^{2} \\ {g}^{ - 1}(x) = \frac{ \sqrt{x} + 3}{2} \\ {g}^{ - 1} (9) = \frac{ \sqrt{9} + 3}{2} = \frac{6}{2} = 3[/tex]