Nilai minimum fungsi f(x)=x^2-2x+9 adalah?

f(x) = x²-2x+9
a=1 , b=-2 dan c =9

[tex]nilai \: minimum = \frac{b^{2} - 4ac }{ - 4a} \\ = \frac{{ - 2}^{2} - 4 \times 9}{ - 4} \\ = \frac{4 - 36}{ - 4} \\ = 8[/tex]
semoga membantu