hasil dari 6 akar 3 + 5 akar 12 dikurang akar 27

[tex]6 \sqrt{3} + 5 \sqrt{12} - \sqrt{27} \\ = 6 \sqrt{3} + 5 \sqrt{4 \times 3} - \sqrt{9 \times 3} \\ = 6 \sqrt{3} + 5 \times 2 \sqrt{3} - 3 \sqrt{3 } \\ = 6 \sqrt{3 } + 10 \sqrt{3} - 3 \sqrt{3} \\ = 13 \sqrt{3} [/tex]
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