hasil dari 3log3+3log54+3log3-3log6 adalah

3log3 + 3log54 + 3log3 - 3log6
= 1 + 3log(27 x 2) + 1 - 3 log(3 x 2)
= 2 + 3log27 + 3log2 - 3 log3 - 3 log2
= 2 + 3log(3)^3 - 1
= 1 + 3. 3log3
= 1 + 3
= 4

Mata Pelajaran : Matematika Peminatan
Kelas : 10
Bab : 02 - Fungsi Logaritma



[tex] {}^{3} log(3) + {}^{3} log(54) + {}^{3} log(3) - {}^{3} log(6) \\ = 1 + {}^{3} log(54) + 1 - {}^{3} log(6) \\ = 2 + {}^{3} log(9) \\ = 2 + {}^{3} log(3 {}^{2} ) \\ = 2 + 2 \\ = 4[/tex]