jika k= { 625 pangkat 1/4 - 64 pangkat 1/6 PER 256 pangkat 1/4 } pangkat -3, nilai 9 k aadalah

Kelas 9 Matematika
Bab Akar dan Pangkat

^ = pangkat

k = (625^(1/4) - 64^(1/6))/(256^(1/4))^-3
k = (5^(4/4) - 2^(6/6))/(4^(4/4))^-3
k = ((5 - 2)/4)^-3
k = (3/4)^-3
k = (4^3)/(3^3)
k = 64/27

Nilai 9k
= 9 . 64/27
= 64/3
= 21 1/3