pake cara ya semuanya

7. 1/ 1/9 = 1 / 0.111 = 9

[tex]( { {2}^{4} })^{2} \times ( { \frac{1}{2} })^{ - 2} \\ = {2}^{4 \times 2} \times \frac{1}{ { \frac{1}{2} }^{2} } \\ = {2}^{8} \times \frac{1}{ \frac{1}{4} } \\ = {2}^{8} \times 4 \\ = {2}^{8} \times {2}^{2} \\ = {2}^{8 + 2} \\ = {2}^{10} \\ \\ \frac{ {a}^{2} {b}^{3} {c}^{4} }{ {ab}^{4} {c}^{2} } \\ = {a}^{2 - 1} {b}^{ 3 - 4} {c}^{4 - 2} \\ = a {b}^{ - 1} {c}^{2} \\ = \frac{ {ac}^{2} }{b} \\ \\ \frac{1}{ { (\frac{1}{3} })^{2} } \\ = \frac{1}{ \frac{1}{9} } \\ = 1 \times \frac{9}{1} \\ = 9 \\ \\ \sqrt{48} + \sqrt{27} - \sqrt{147} \\ = \sqrt{16 \times 3} + \sqrt{9 \times 3} - \sqrt{49 \times 3} \\ = 4 \sqrt{3} + 3 \sqrt{3} - 7 \sqrt{3} \\ = 7 \sqrt{3} - 7 \sqrt{3} \\ = 0 \\ \\ \frac{{ \sqrt{6} \times \sqrt{2} } }{ \sqrt{3} } \\ = \frac{ \sqrt{12} }{ \sqrt{3} } \\ = \sqrt{4} \\ = 2 \\ \\ semoga \: membantu[/tex]