tolong bantu mengerjakan yg no 2 dengan caranya please!

sin 60° / 18 = sin 90/QR
1/2 √3 /18 = 1/QR
1/2 √3 QR = 18
√3 QR = 36
QR = 36/√3
QR = 36/√3 x √3/√3
QR = 36√3 : 3
QR = 12 √3 cm

sin 60°/18 = sin 30°/PR
1/2 √3/18 = 1/2 /PR
1/2 √3 PR = 1/2 x 18
√3 PR = 18
PR = 18/√3 x √3/√3
PR = 18√3/3
PR = 6 √3

Mata Pelajaran : Matematika
Materi : Trigonometri

2.
sin 60 = PQ / QR
Akar 3 / 2 = 18 / QR
QR Akar 3 = 36
QR = 36 / Akar 3
QR = 12 akar 3 / 3 cm

cos 60 = PR / QR
1 / 2 = PR / 12 akar 3 / 3
2 PR = 12 akar 3 / 3
PR = 12 akar 3 / 6
PR = 2 akar 3 cm

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